Question:

250 mL of a waste solution obtained from the workshop of a goldsmith contains 0.1 M AgNO3 and 0.1 M AuCl. The solution was electrolyzed at 2V by passing a current of 1A for 15 minutes. The metal/metals electrodeposited will be
[ \(E^0_{Ag^+/Ag} = 0.80\ \mathrm{V}\), \(E^0_{Au^+/Au} = 1.69\ \mathrm{V}\) ]

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The ion with the higher reduction potential is discharged first; check whether the charge passed is enough to deplete \(\mathrm{Au^+}\).
Updated On: Nov 5, 2026
  • Silver and gold in equal mass proportion
  • Silver and gold in proportion to their atomic weights
  • Only gold
  • Only silver
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The Correct Option is C

Solution and Explanation

Charge passed: \(Q = It = 1 \times 15 \times 60 = 900\ \mathrm{C}\), i.e. \(\dfrac{900}{96500} = 9.3\times10^{-3}\) mol of electrons.
Amount of \(\mathrm{Au^+}\) present: \(0.25\ \mathrm{L}\times 0.1\ \mathrm{M} = 0.025\) mol, which needs 0.025 mol of electrons for complete deposition (more than the 0.0093 mol supplied).
\(\mathrm{Au^+}\) has the higher reduction potential (1.69 V against 0.80 V), so it is reduced first at the cathode and, since it is not exhausted, the cathode potential stays near 1.6 V, far above that needed for \(\mathrm{Ag^+}\). Hence silver does not deposit.
Only gold is deposited.
Answer: (3) Only gold
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