Question:

\( ^{20}P_3 - ^{19}P_3 = \)

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The identity \(^nP_r - ^{n-1}P_r = r \cdot ^{n-1}P_{r-1}\) is a useful shortcut for simplifying differences of permutations. It arises from considering whether the nth object is included in the permutation or not.
Updated On: Mar 30, 2026
  • \( ^{19}P_4 \)
  • \( 4(^{19}P_4) \)
  • \( 5!(646) \)
  • \( 6!(646) \)
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The Correct Option is D

Solution and Explanation

We need to evaluate the expression \( ^{20}P_3 - ^{19}P_3 \).
Using the formula for permutations, \( ^nP_r = \frac{n!}{(n-r)!} \).
\( ^{20}P_3 = \frac{20!}{(20-3)!} = \frac{20!}{17!} = 20 \times 19 \times 18 = 6840 \).
\( ^{19}P_3 = \frac{19!}{(19-3)!} = \frac{19!}{16!} = 19 \times 18 \times 17 = 5814 \).
So, \( ^{20}P_3 - ^{19}P_3 = 6840 - 5814 = 1026 \).
Alternatively, we can use the identity \(^nP_r = ^{n-1}P_r + r \cdot ^{n-1}P_{r-1}\).
Rearranging, we get \(^nP_r - ^{n-1}P_r = r \cdot ^{n-1}P_{r-1}\).
For this problem, \(n=20\) and \(r=3\).
\(^{20}P_3 - ^{19}P_3 = 3 \cdot ^{19}P_{2}\).
\(^{19}P_2 = 19 \times 18 = 342\).
So, the expression equals \(3 \times 342 = 1026\).
There appears to be a significant discrepancy between the calculated result (1026) and the provided options. The value of option (D) is \(6!(646) = 720 \times 646 = 465120\). This indicates a probable error in the question or the options. However, adhering to the provided answer key, the correct option is stated as (D).
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