Question:

17 × 17 × 18 × 18 × 19 × 19 shall be fully divisible by which of the following number?

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Express the number in prime factors to check divisibility easily.
Updated On: Mar 26, 2026
  • 971
  • 173
  • 646
  • 233
  • 5813
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The Correct Option is C

Solution and Explanation


Step 1:
Understanding the Expression:
Expression = \(17^2 \times 18^2 \times 19^2 = (17 \times 18 \times 19)^2\)

Step 2:
Calculating the Product:
\(17 \times 18 = 306\)
\(306 \times 19 = 5814\)
So, expression = \(5814^2\)

Step 3:
Checking Divisibility:
\(5814 = 2 \times 2907 = 2 \times 3 \times 969 = 2 \times 3 \times 3 \times 323 = 2 \times 3^2 \times 17 \times 19\)
So, \(5814^2 = 2^2 \times 3^4 \times 17^2 \times 19^2\)
Now, 646 = \(2 \times 17 \times 19\)
Since the expression has \(2^2\), \(17^2\), and \(19^2\), it is divisible by \(2 \times 17 \times 19 = 646\).
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