Question:
10g of water at \(100\degree C \)is converted into steam at the same temperature. If the latent heat of steam is 540cal/g, the change in entropy is
10g of water at \(100\degree C \)is converted into steam at the same temperature. If the latent heat of steam is 540cal/g, the change in entropy is
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Often, ∆S =mL/T. Watch out for potential factor-of-10 mismatches in the given options or question statements.
Updated On: Feb 11, 2026
- 14.47 cal/K
- 144.7 cal/K
- 74.47 cal/K
- 47.47 cal/K
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The Correct Option is A
Solution and Explanation
Heat absorbed, $Q = m L = 10 \text{ g} \times 540 \text{ cal/g} = 5400 \text{ cal}$.
At $100^\circ \text{C}$, the temperature in Kelvin is $T = 373 \text{ K}$. Change in entropy:
$\Delta S = \frac{Q}{T} = \frac{5400 \text{ cal}}{373 \text{ K}} \approx 14.48 \text{ cal/K}.$
The official “closest” or typical reported answer is $14.47 \text{ cal/K}$. Possibly the question includes a factor of 10 or an alternative unit interpretation
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