Question:

10 L vessel contains He (0.4 g), O$_2$ (1.6 g), N$_2$ (1.4 g). Find partial pressure of He at 300 K.

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Partial pressure depends only on moles of that gas.
Updated On: Jun 17, 2026
  • 0.123 atm
  • 0.246 atm
  • 0.323 atm
  • 0.133 atm
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The Correct Option is B

Solution and Explanation


Step 1: Moles of He: \[ n = \frac{0.4}{4} = 0.1 \]
Step 2: Ideal gas law for partial pressure: \[ P = \frac{nRT}{V} \]
Step 3: Substitute: \[ P = \frac{0.1 \times 0.0821 \times 300}{10} \]
Step 4: \[ P = \frac{2.463}{10} = 0.2463 \approx 0.246 \]
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