Question:
\(∫\frac{1}{x[6(logx)^2+7logx+2]}dx=\)
\(∫\frac{1}{x[6(logx)^2+7logx+2]}dx=\)
Updated On: Apr 26, 2024
- \(\frac{1}{2}log|\frac{2logx+1}{3logx+2}|+C\)
- \(log|\frac{2logx+1}{3logx+2}|+C\)
- \(log|\frac{3logx+2}{2logx+1}|+C\)
- \(\frac{1}{2}log|\frac{3logx+2}{2logx+1}|+C\)
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The Correct Option is B
Solution and Explanation
The correct answer is Option (B) : \(log|\frac{2logx+1}{3logx+2}|+C\)
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