Question:

1.4 g of an organic compound was digested according to Kjeldahl's method and the ammonia evolved was absorbed in 60 mL of M/10 \(\mathrm{H_2SO_4}\) solution. The excess sulphuric acid required 20 mL of M/10 NaOH solution for neutralization. The percentage of nitrogen in the compound is:

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Find the milliequivalents of acid neutralised by \(\mathrm{NH_3}\), then \(\%\ \mathrm{N} = \frac{1.4 \times \text{meq}}{\text{mass of compound}}\).
Updated On: Nov 11, 2026
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The Correct Option is D

Solution and Explanation

Total acid = 60 mL of M/10 \(\mathrm{H_2SO_4}\) = 60 \(\times\) 0.2 N = 12 meq.
NaOH used for the excess = 20 \(\times\) 0.1 = 2 meq, so excess acid = 2 meq.
Acid neutralised by \(\mathrm{NH_3}\) = 12 - 2 = 10 meq.
\(\%\ \mathrm{N} = \frac{1.4 \times 10}{1.4} = 10\%\).
Answer: (4) 10
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