Concept:
Prokaryotic cells are the simplest and most primitive cellular organisms. They lack a true nucleus and membrane-bound organelles. Their genetic material remains in direct contact with the cytoplasm and is present in a nucleoid region. Bacteria, cyanobacteria and mycoplasma are examples of prokaryotes.
To identify the correct characteristics of prokaryotic cells, let us examine each statement individually.
Analysis of Statement (a): Ribosomes are made of 50S and 30S subunits
The ribosomes present in prokaryotic cells are of the 70S type.
A 70S ribosome consists of:
\[
50S + 30S = 70S
\]
where:
• 50S is the larger subunit.
• 30S is the smaller subunit.
These ribosomes are responsible for protein synthesis in bacteria and other prokaryotes.
Therefore, statement (a) is
correct.
Analysis of Statement (b): They can have plasmids
Plasmids are small circular double-stranded DNA molecules that exist independently of the main bacterial chromosome.
They:
• Replicate independently.
• Often carry antibiotic resistance genes.
• Can be transferred from one bacterium to another.
• Are widely used in genetic engineering as vectors.
Since plasmids are commonly found in prokaryotes, statement (b) is
correct.
Analysis of Statement (c): They contain mesosome
Mesosomes are infoldings of the plasma membrane reported in prokaryotic cells.
According to NCERT:
• Mesosomes are extensions of the plasma membrane.
• They help in cell wall formation.
• They assist in DNA replication and distribution to daughter cells.
• They increase the surface area of the plasma membrane.
Hence statement (c) is
correct.
Analysis of Statement (d): They have peroxisomes
Peroxisomes are membrane-bound organelles.
They are present only in eukaryotic cells and contain enzymes involved in:
• Breakdown of hydrogen peroxide.
• Oxidative metabolism.
• Detoxification reactions.
Since prokaryotic cells lack membrane-bound organelles, they do not possess peroxisomes.
Therefore statement (d) is
incorrect.
Thus:
\[
(a),\ (b),\ (c)
\]
are correct and
\[
(d)
\]
is incorrect.
Hence the correct answer is
\[
\boxed{(1)\ (a),\ (b)\ \text{and}\ (c)\ \text{only}}
\]