Concept:
The area of a triangle is calculated using the formula:
\[
\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}
\]
In a rectangle $ABCD$, if point $E$ lies on side $AD$, the height of both $\triangle ABE$ and $\triangle ECD$ corresponds to the breadth of the rectangle, which we denote as $AB$ (given $AB = CD$).
Step 1: Analyze the given statements for dimensions and relationships.
Statement (I) provides the total area of the rectangle $ABCD$:
\[
\text{Area}(ABCD) = AB \times AD = 54
\]
Statement (II) provides the geometric relationship between the segments $AE$ and $ED$:
\[
AE = 2 ED
\]
Step 2: Combine the information to express the total side length $AD$.
Since the point $E$ lies on $AD$, the total length is the sum of the two segments:
\[
AD = AE + ED
\]
Substituting the ratio from Statement (II) into this equation:
\[
AD = 2 ED + ED = 3 ED
\]
Step 3: Calculate the value of the product of $AB$ and $ED$ using the area from Statement (I).
Substitute the expression for $AD$ into the rectangle area formula:
\[
AB \times (3 ED) = 54
\]
Dividing both sides by 3 to isolate the product:
\[
AB \times ED = 18
\]
Step 4: Determine the total area of the shaded region.
The shaded area is the sum of the areas of the two triangles:
\[
\text{Area}_{\text{shaded}} = \text{Area}(\triangle ABE) + \text{Area}(\triangle ECD)
\]
\[
\text{Area}_{\text{shaded}} = \left( \frac{1}{2} \times AB \times AE \right) + \left( \frac{1}{2} \times CD \times ED \right)
\]
Substitute $CD = AB$ and $AE = 2 ED$ into the equation:
\[
\text{Area}_{\text{shaded}} = \left( \frac{1}{2} \times AB \times 2 ED \right) + \left( \frac{1}{2} \times AB \times ED \right)
\]
Simplify the expression:
\[
\text{Area}_{\text{shaded}} = (AB \times ED) + \left( \frac{1}{2} \times AB \times ED \right)
\]
Substitute $AB \times ED = 18$ into the result:
\[
\text{Area}_{\text{shaded}} = 18 + 9 = 27
\]