Question:

The time period of a simple pendulum of length $l$ is $T$. If its length is increased to $4l$, its new time period will be

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Remember that for a simple pendulum, doubling the length results in a doubling of the time period due to the square root relationship in the formula.
Updated On: May 31, 2026
  • $2T$
  • $4T$
  • $T/2$
  • $T$
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The Correct Option is A

Solution and Explanation


Step 1: Concept

The time period \( T \) of a simple pendulum is given by the formula: \[T = 2\pi \sqrt{\frac{l}{g}}\] where \( l \) is the length of the pendulum and \( g \) is the acceleration due to gravity.

Step 2: Meaning

This means that the time period depends on the square root of the length of the pendulum. If we increase the length, the time period will also increase proportionally according to this relationship.

Step 3: Analysis

Given: Original length: \( l \) Original time period: \( T = 2\pi \sqrt{\frac{l}{g}} \) When the length is increased to \( 4l \): \[T_{\text{new}} = 2\pi \sqrt{\frac{4l}{g}}\] We can simplify this expression: \[T_{\text{new}} = 2\pi \sqrt{4} \cdot \sqrt{\frac{l}{g}}\] \[T_{\text{new}} = 2\pi \cdot 2 \cdot \sqrt{\frac{l}{g}}\] \[T_{\text{new}} = 2 \cdot (2\pi \sqrt{\frac{l}{g}})\] \[T_{\text{new}} = 2T\] Thus, the new time period is twice the original time period.

Step 4: Conclusion

The time period of a simple pendulum increases proportionally with the square root of its length. When the length is quadrupled, the time period doubles. Final Answer: (A)
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