Step 1: Acetaldehyde (CH3-CHO) reacts with hydroxylamine (H2NOH) to form acetaldoxime (CH3-CH=N-OH) and water.
Step 2: The mechanism begins with nucleophilic addition, the -NH2 group of hydroxylamine attacks the electrophilic carbonyl carbon of the aldehyde, forming an unstable addition intermediate.
Step 3: This intermediate then loses a molecule of water. The final product is the oxime, where a C=N double bond has replaced the original C=O double bond.
Step 4: A reaction where two molecules join together and a small molecule such as water is released at the same time is classified as a condensation reaction. A simple addition reaction alone would not release any water, since nothing would be lost from the combined system.
Step 5: Since water is eliminated as the two reactants unite, this is correctly called a condensation reaction. Answer: B) Condensation reaction.