Step 1: Concept
Escape velocity $v_e = \sqrt{\frac{2GM}{R}}$ and Orbital velocity $v_o = \sqrt{\frac{GM}{R}}$.
Step 2: Meaning
We need the ratio $\frac{v_e}{v_o}$.
Step 3: Analysis
$\frac{v_e}{v_o} = \frac{\sqrt{2GM/R}}{\sqrt{GM/R}} = \sqrt{2}$.
Step 4: Conclusion
The ratio is $\sqrt{2} : 1$.
Final Answer: (B)