Question:
The ratio of equivalent weights of $HNO_{3}$ and $H_{2}SO_{4}$ is
The ratio of equivalent weights of $HNO_{3}$ and $H_{2}SO_{4}$ is
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Basicity is the number of replaceable $H^{+}$ ions. $HNO_{3}$ is monobasic, $H_{2}SO_{4}$ is dibasic.
Updated On: Jul 4, 2026
- 9:5
- 6:5
- 7:9
- 9:7
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The Correct Option is D
Solution and Explanation
Step 1: Concept
Equivalent weight of an acid $= \text{Molecular Weight} / \text{Basicity}$.
Step 2: Meaning
$HNO_{3}$ has a molecular weight of 63 and basicity of 1. $H_{2}SO_{4}$ has a molecular weight of 98 and basicity of 2.
Step 3: Analysis
Eq. wt of $HNO_{3} = 63 / 1 = 63$. Eq. wt of $H_{2}SO_{4} = 98 / 2 = 49$.
Step 4: Conclusion
The ratio is $63:49$. Dividing both by 7 gives $9:7$. Final Answer: (D)
Equivalent weight of an acid $= \text{Molecular Weight} / \text{Basicity}$.
Step 2: Meaning
$HNO_{3}$ has a molecular weight of 63 and basicity of 1. $H_{2}SO_{4}$ has a molecular weight of 98 and basicity of 2.
Step 3: Analysis
Eq. wt of $HNO_{3} = 63 / 1 = 63$. Eq. wt of $H_{2}SO_{4} = 98 / 2 = 49$.
Step 4: Conclusion
The ratio is $63:49$. Dividing both by 7 gives $9:7$. Final Answer: (D)
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