Question:
The pH and pOH of 0.1 M sulphuric acid are: (\(H_2SO_4\) dissociates completely to give 2 \(H^+\) ions per formula unit; \(pK_w = 14\))
The pH and pOH of 0.1 M sulphuric acid are: (\(H_2SO_4\) dissociates completely to give 2 \(H^+\) ions per formula unit; \(pK_w = 14\))
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H2SO4 gives 2 H+ ions per molecule; use pH + pOH = 14.
Updated On: Jul 3, 2026
- 0.1, 13.9
- 0.3, 13.7
- 0.7, 13.3
- 1.0, 13.0
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The Correct Option is C
Solution and Explanation
Step 1: [H+]=2x0.1=0.2M.
Step 2: pH=-log(0.2)=0.7.
Step 3: pOH=14-0.7=13.3.
\[\boxed{pH = 0.7,\ pOH = 13.3}\]Was this answer helpful?
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