Question:

The number of ways in which 6 boys and 4 girls can be seated around a round table such that 2 special boys and a special girl never sit together is

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Total ways - Together = Not Together.
Updated On: Jun 19, 2026
  • 332620
  • 332540
  • 332640
  • 332520
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The Correct Option is C

Solution and Explanation

Step 1: Concept
Total circular arrangements of $n$ people is $(n-1)!$.

Step 2: Analysis

Total arrangements of 10 people $= 9! = 362880$.
Let the 3 special people (2 boys, 1 girl) be one unit.
Arrangements where they are together $= (8-1)! \times 3! = 7! \times 6 = 5040 \times 6 = 30240$.

Step 3: Calculation

Ways where they are NOT together $= 362880 - 30240 = 332640$.

Step 4: Conclusion

Hence, the number of ways is 332640. Final Answer: (C)
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