Question:
The number of \(sp^2\), \(sp^3\) hybridised carbons in cumene, respectively are:
The number of \(sp^2\), \(sp^3\) hybridised carbons in cumene, respectively are:
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All carbon atoms in a benzene ring are \(sp^2\) hybridised, whereas alkyl side-chain carbons attached through single bonds are generally \(sp^3\) hybridised.
Updated On: Jun 26, 2026
- \(6,2\)
- \(3,6\)
- \(6,3\)
- \(4,4\)
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The Correct Option is C
Solution and Explanation
Step 1: Write the structure of cumene.
Cumene is isopropyl benzene. Its structure is \[ C_6H_5-CH(CH_3)_2 \] It contains a benzene ring attached to an isopropyl group.
Step 2: Count the \(sp^2\) hybridised carbons.
All six carbon atoms of the benzene ring are \[ sp^2 \] hybridised because each carbon participates in the delocalized \(\pi\)-electron system.
Therefore, \[ \text{Number of } sp^2 \text{ carbons}=6 \]
Step 3: Count the \(sp^3\) hybridised carbons.
The isopropyl group is \[ -CH(CH_3)_2 \] It contains: \[ 1 \text{ central carbon} \] and \[ 2 \text{ methyl carbons} \] All three carbons form only single bonds and hence are \[ sp^3 \] hybridised.
Therefore, \[ \text{Number of } sp^3 \text{ carbons}=3 \]
Step 4: Final conclusion.
Hence, the number of \(sp^2\) and \(sp^3\) hybridised carbons in cumene are \[ \boxed{6,3} \] Therefore, the correct option is \[ \boxed{(3)} \]
Cumene is isopropyl benzene. Its structure is \[ C_6H_5-CH(CH_3)_2 \] It contains a benzene ring attached to an isopropyl group.
Step 2: Count the \(sp^2\) hybridised carbons.
All six carbon atoms of the benzene ring are \[ sp^2 \] hybridised because each carbon participates in the delocalized \(\pi\)-electron system.
Therefore, \[ \text{Number of } sp^2 \text{ carbons}=6 \]
Step 3: Count the \(sp^3\) hybridised carbons.
The isopropyl group is \[ -CH(CH_3)_2 \] It contains: \[ 1 \text{ central carbon} \] and \[ 2 \text{ methyl carbons} \] All three carbons form only single bonds and hence are \[ sp^3 \] hybridised.
Therefore, \[ \text{Number of } sp^3 \text{ carbons}=3 \]
Step 4: Final conclusion.
Hence, the number of \(sp^2\) and \(sp^3\) hybridised carbons in cumene are \[ \boxed{6,3} \] Therefore, the correct option is \[ \boxed{(3)} \]
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