Concept:
\[
[x]
\]
(the greatest integer function) is discontinuous at every integer, whereas
\[
|x-2|
\]
is continuous for all real \(x\).
Therefore, discontinuities of
\[
f(x)=[x]+|x-2|
\]
can occur only at integer points.
Step 1: List all integers in the interval \((-3,3)\).
The integers lying in
\[
-3<x<3
\]
are
\[
-2,\,-1,\,0,\,1,\,2.
\]
Step 2: Check discontinuity at these points.
Since
\[
|x-2|
\]
is continuous everywhere, adding it does not remove the jump discontinuity of
\[
[x].
\]
At every integer \(n\),
\[
\lim_{x\to n^-}[x]=n-1,
\]
\[
\lim_{x\to n^+}[x]=n.
\]
Hence the jump is
\[
1.
\]
Therefore \(f(x)\) is discontinuous at each of
\[
-2,\,-1,\,0,\,1,\,2.
\]
Step 3: Count the discontinuity points.
Number of discontinuity points
\[
=5.
\]
Step 4: Write the final answer.
\[
\boxed{5}
\]