Question:
The number of Pi ($\pi$) bonds in $C_2H_4, C_2H_2$ and $C_2N_2$ is x, y and z respectively. The sum of x, y and z is equal to:
The number of Pi ($\pi$) bonds in $C_2H_4, C_2H_2$ and $C_2N_2$ is x, y and z respectively. The sum of x, y and z is equal to:
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Double bond = 1 $\sigma$, 1 $\pi$; Triple bond = 1 $\sigma$, 2 $\pi$.
Updated On: Jun 10, 2026
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The Correct Option is B
Solution and Explanation
Step 1: Concept
Determining $\pi$ bonds in chemical structures.
Step 2: Analysis
* $C_2H_4$ ($CH_2=CH_2$): 1 $\pi$ bond ($x=1$). * $C_2H_2$ ($HC \equiv CH$): 2 $\pi$ bonds ($y=2$). * $C_2N_2$ ($N \equiv C-C \equiv N$): The structure has a triple bond on each end, totaling 4 $\pi$ bonds ($z=4$).
Step 3: Conclusion
Sum $x+y+z = 1+2+4 = 7$.
Final Answer: (B)
Determining $\pi$ bonds in chemical structures.
Step 2: Analysis
* $C_2H_4$ ($CH_2=CH_2$): 1 $\pi$ bond ($x=1$). * $C_2H_2$ ($HC \equiv CH$): 2 $\pi$ bonds ($y=2$). * $C_2N_2$ ($N \equiv C-C \equiv N$): The structure has a triple bond on each end, totaling 4 $\pi$ bonds ($z=4$).
Step 3: Conclusion
Sum $x+y+z = 1+2+4 = 7$.
Final Answer: (B)
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