Question:
The floor of hall of dimensions \(18\,m \times 12\,m\) is to be fixed by tiles of size \(45\,cm \times 15\,cm\). The number of tiles required for the floor of the hall is:
The floor of hall of dimensions \(18\,m \times 12\,m\) is to be fixed by tiles of size \(45\,cm \times 15\,cm\). The number of tiles required for the floor of the hall is:
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Always convert all dimensions into the same unit before solving area problems.
Updated On: Jun 15, 2026
- \(2900 \)
- \(3200 \)
- \(4000 \)
- \(4800 \)
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The Correct Option is B
Solution and Explanation
Concept:
Area method is used for tile problems.
Step 1: Convert all units into cm.
\[ 18m = 1800cm, \quad 12m = 1200cm \]
Step 2: Find area of floor.
\[ 1800 \times 1200 = 2160000 \]
Step 3: Find area of one tile.
\[ 45 \times 15 = 675 \]
Step 4: Divide areas.
\[ \frac{2160000}{675} = 3200 \]
Step 1: Convert all units into cm.
\[ 18m = 1800cm, \quad 12m = 1200cm \]
Step 2: Find area of floor.
\[ 1800 \times 1200 = 2160000 \]
Step 3: Find area of one tile.
\[ 45 \times 15 = 675 \]
Step 4: Divide areas.
\[ \frac{2160000}{675} = 3200 \]
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