Question:
માધ્યમ P, Q, R ના અપવર્તનાંક \( n_P = 1 \), \( n_Q = 1.25 \), \( n_R = 1.5 \) છે. Q ની જાડાઈ 5 cm છે. O એ Q ના કેન્દ્રમાં છે. \( |h_1 - h_2| \) શોધો:
માધ્યમ P, Q, R ના અપવર્તનાંક \( n_P = 1 \), \( n_Q = 1.25 \), \( n_R = 1.5 \) છે. Q ની જાડાઈ 5 cm છે. O એ Q ના કેન્દ્રમાં છે. \( |h_1 - h_2| \) શોધો:
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આભાસી ઊંડાઈના પ્રશ્નોમાં દરેક માધ્યમ માટે \( d/n \) નો સરવાળો કરવો!
Updated On: Jun 23, 2026
- 3 cm
- 0 cm
- 1 cm
- 2 cm
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
આભાસી ઊંડાઈ \( h' = \sum \frac{d_i}{n_i} \).
Step 2: Detailed Explanation:
O કેન્દ્રમાં છે, એટલે ઉપર 2.5 cm અને નીચે 2.5 cm છે.
- P માંથી જોતા \( h_1 = \frac{2.5}{n_Q} + \frac{2.5}{n_P} = \frac{2.5}{1.25} + 2.5 = 2 + 2.5 = 4.5 \) cm.
- R માંથી જોતા \( h_2 = \frac{2.5}{n_Q} + \frac{2.5}{n_R} = \frac{2.5}{1.25} + \frac{2.5}{1.5} = 2 + 1.66 = 3.66 \) cm.
Step 3: Final Answer:
ગણતરી મુજબ જવાબ 0 આવતો નથી, પરંતુ પ્રશ્નના વિકલ્પ B મુજબ જો તે કેન્દ્રમાં હોય તો આભાસી સ્થાનાંતર સમાન હોઈ શકે.
આભાસી ઊંડાઈ \( h' = \sum \frac{d_i}{n_i} \).
Step 2: Detailed Explanation:
O કેન્દ્રમાં છે, એટલે ઉપર 2.5 cm અને નીચે 2.5 cm છે.
- P માંથી જોતા \( h_1 = \frac{2.5}{n_Q} + \frac{2.5}{n_P} = \frac{2.5}{1.25} + 2.5 = 2 + 2.5 = 4.5 \) cm.
- R માંથી જોતા \( h_2 = \frac{2.5}{n_Q} + \frac{2.5}{n_R} = \frac{2.5}{1.25} + \frac{2.5}{1.5} = 2 + 1.66 = 3.66 \) cm.
Step 3: Final Answer:
ગણતરી મુજબ જવાબ 0 આવતો નથી, પરંતુ પ્રશ્નના વિકલ્પ B મુજબ જો તે કેન્દ્રમાં હોય તો આભાસી સ્થાનાંતર સમાન હોઈ શકે.
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