Question

One Palla of Tigun in Teentaal consists of how many matras ?

• A. \(5\frac{1}{3}\)
• B. \(5\frac{1}{2}\)
• C. \(5\frac{1}{4}\)
• D. 6

Hint:

To find the matra length of one Palla in a seamless triplet division, simply divide the total matras of the taal by 3. For Teentaal: \(\frac{16}{3} = 5\frac{1}{3}\) matras.

Answer 1

The Correct Option is A

Concept: A standard mathematical *Tihai* consists of three identical rhythmic phrases called Pallas, separated by two equal pauses (Dums). When a composition is set up to land perfectly on the Sam without any internal pauses (Anadi Tihai), the total mathematical length matches the cycle's target count. However, when evaluating a basic multi-cycle division like a single symmetrical section of a triplet subdivision (*Tigun*), we analyze the note-span per phrase block.

Step 1: Determine the basic parameters of Teentaal and Tigun.

• Teentaal consists of a total length of 16 matras.
• Tigun (triple speed) means that each matra contains exactly 3 structural notes or letter units.
• Therefore, the total number of note units available in one full cycle of Teentaal at triple speed is: \[ 16 \text{ matras} \times 3 \text{ notes/matra} = 48 \text{ units} \]

Step 2: Divide the total note span into three equal parts.
To find the length of one single *Palla* that spans across this triplet layer, divide the total notes by 3: \[ \text{Notes per Palla} = \frac{48}{3} = 16 \text{ notes} \] Now, convert these 16 note units back into standard matra counts by dividing by the speed factor (3): \[ \text{Matras per Palla} = \frac{16}{3} = 5\frac{1}{3} \text{ matras} \]