Question:
Match the following:
List-I Name of Polymer List-II Monomers A Glyptal I Ethylene glycol + Terephthalic acid B Nylon 6,6 II Glycine + Amino caproic acid C Terylene III Adipic acid + Hexamethylene diamine D Nylon 2,6 IV Ethane-1,2-diol + Phthalic acid
Match the following:
| List-I | Name of Polymer | List-II | Monomers |
|---|---|---|---|
| A | Glyptal | I | Ethylene glycol + Terephthalic acid |
| B | Nylon 6,6 | II | Glycine + Amino caproic acid |
| C | Terylene | III | Adipic acid + Hexamethylene diamine |
| D | Nylon 2,6 | IV | Ethane-1,2-diol + Phthalic acid |
Show Hint
Memory trick:
Glyptal = Phthalic acid
Terylene = Terephthalic acid
Nylon 6,6 = 6C + 6C
Nylon 2,6 = 2C + 6C
Updated On: Jun 13, 2026
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The Correct Option is B
Solution and Explanation
Concept:
These are condensation polymers formed by esterification or amide formation.
Step 1: Glyptal \[ \text{Ethylene glycol + Phthalic acid} \Rightarrow \text{A--IV} \]
Step 2: Nylon 6,6 \[ \text{Hexamethylene diamine + Adipic acid} \Rightarrow \text{B--III} \]
Step 3: Terylene \[ \text{Ethylene glycol + Terephthalic acid} \Rightarrow \text{C--I} \]
Step 4: Nylon 2,6 \[ \text{Glycine + Amino caproic acid} \Rightarrow \text{D--II} \]
Step 1: Glyptal \[ \text{Ethylene glycol + Phthalic acid} \Rightarrow \text{A--IV} \]
Step 2: Nylon 6,6 \[ \text{Hexamethylene diamine + Adipic acid} \Rightarrow \text{B--III} \]
Step 3: Terylene \[ \text{Ethylene glycol + Terephthalic acid} \Rightarrow \text{C--I} \]
Step 4: Nylon 2,6 \[ \text{Glycine + Amino caproic acid} \Rightarrow \text{D--II} \]
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