Question

IUPAC names of the following compounds \(X\) and \(Y\) are respectively

• A. 2-Bromo-4-methylpent-3-ene ; 3-Ethoxy phenyl ethane
• B. 2-Bromo-4-methylpent-3-ene ; 1-Ethyl-3-ethoxy benzene
• C. 4-Bromo-2-methylpent-2-ene ; 1-Ethoxy-3-ethyl benzene
• D. 4-Bromo-2-methylpent-2-ene ; 3-Ethoxy phenyl ethane

Hint:

For IUPAC nomenclature, \[ \boxed{\text{Give the double bond the lowest possible locant.}} \] For substituted benzene, \[ \boxed{\text{If locants are the same, assign position 1 alphabetically.}} \]

Answer 1

The Correct Option is C

Step 1: Name compound \(X\). Choose the longest chain containing the double bond. Number the chain from the end nearest the double bond. \[ \mathrm{CH_3CH(Br)CH=C(CH_3)_2} \] gives \[ \boxed{\text{4-Bromo-2-methylpent-2-ene}.} \]

Step 2: Name compound \(Y\). The benzene ring contains \[ \mathrm{-OC_2H_5} \] (ethoxy) and \[ \mathrm{-C_2H_5} \] (ethyl) groups in the meta position. Using the lowest set of locants and alphabetical order, \[ \boxed{\text{1-Ethoxy-3-ethyl benzene}.} \]

Step 3: Write the answer. Therefore, the correct pair of IUPAC names is \[ \boxed{\text{4-Bromo-2-methylpent-2-ene ; 1-Ethoxy-3-ethyl benzene}.} \] Thus, \[ \boxed{(C)} \] is the correct answer.