Step 1: Determine the oxidation state of Mn.& nbsp;
\[ \begin{aligned} \mathrm{KMnO_4} & amp;: +7,\\ \mathrm{K_2MnO_4} & amp;: +6,\\ \mathrm{Mn_2O_7} & amp;: +7,\\ \mathrm{MnO_2} & amp;: +4. \end{aligned} \]
Step 2: Compare ionic sizes.
The ionic size decreases with an increase in oxidation state due to greater effective nuclear attraction.
Among the given compounds,
\[ \mathrm{Mn^{4+}} \]
has the lowest oxidation state.
Therefore, it has the largest ionic size.
Step 3: Write the answer.
Hence,
\[ \boxed{\mathrm{MnO_2}}. \]
Thus, the correct option is
\[ \boxed{(D)}. \]
| Molisch's lest | Barfoed Test | Biuret Test | |
|---|---|---|---|
| A | Positive | Negative | Negativde |
| B | Positive | Positive | Negative |
| C | Negative | Negative | Positive |
The set of elements which obey the general electronic configuration \( (n-1)d^{10} ns^2 \) is:}