Question

In which of the following, carbon uses \(sp^3\) hybrid orbital for bond formation with oxygen?

• A. Formic acid
• B. Urea
• C. t-Butyl alcohol
• D. Acetaldehyde

Hint:

A carbon atom bonded to oxygen through \[ \boxed{\text{only single bonds}} \] is generally \[ \boxed{sp^3\text{-hybridized}.} \] A carbonyl carbon \[ (\mathrm{C=O}) \] is always \[ \boxed{sp^2\text{-hybridized}.} \]

Answer 1

The Correct Option is C

Step 1: Identify the hybridization of carbon bonded to oxygen. In \[ \text{t-Butyl alcohol } \left((\mathrm{CH_3})_3\mathrm{COH}\right), \] the carbon attached to the hydroxyl group forms four single bonds. Hence, it is \[ \boxed{sp^3\text{-hybridized}.} \]

Step 2: Examine the remaining compounds. In formic acid, urea and acetaldehyde, the carbon bonded to oxygen is part of a carbonyl group \[ (\mathrm{C=O}), \] which is \[ \boxed{sp^2\text{-hybridized}.} \] Therefore, these compounds do not satisfy the condition.

Step 3: Choose the correct option. Hence, \[ \boxed{\text{t-Butyl alcohol}} \] is the correct answer. Therefore, the correct option is \(\boxed{(C)}\).