Step 1: Concept
In a pipe closed at one end, only odd harmonics are present ($f, 3f, 5f, 7f \dots$).
Step 2: Meaning
The first three overtones correspond to the 3rd, 5th, and 7th harmonics.
Step 3: Analysis
Sum $= 3f + 5f + 7f = 15f$. Given $15f = 3930 \text{ Hz}$. $f = \frac{3930}{15}$.
Step 4: Conclusion
$f = 262 \text{ Hz}$.
Final Answer: (B)