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in a solar system the time period of revolution of
Question:
In a solar system, the time period of revolution of a planet tracing a circular orbit of radius \(R\) is proportional to:
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Remember Kepler's Third Law: \[ T^2\propto R^3 \] For quick questions directly write \[ T\propto R^{3/2} \]
NEET (UG) - 2026
NEET (UG)
Updated On:
Jun 21, 2026
\(R^3\)
\(R^{1/2}\)
\(R^{3/2}\)
\(R^2\)
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The Correct Option is
C
Solution and Explanation
Concept:
• Kepler's Third Law states: \[ T^2 \propto R^3 \] for planets revolving around the same star.
Step 1:
Write the gravitational force.
\[ \frac{GMm}{R^2} \] This provides the necessary centripetal force. \[ \frac{GMm}{R^2} = m\frac{v^2}{R} \]
Step 2:
Express velocity in terms of time period.
\[ v=\frac{2\pi R}{T} \] Substituting, \[ \frac{GM}{R^2} = \frac{4\pi^2R}{T^2} \]
Step 3:
Find the relation between \(T\) and \(R\).
\[ T^2 = \frac{4\pi^2R^3}{GM} \] Therefore, \[ T^2\propto R^3 \] \[ T\propto R^{3/2} \] \[ \boxed{\text{Option (C)}} \]
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