Question:

If variance of \(X\) is \(4\), then the variance of \(Y=4X+2\) is

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For \[ Y=aX+b, \] \[ \boxed{\operatorname{Var}(Y)=a^2\operatorname{Var}(X).} \] Adding a constant does not affect variance.
Updated On: Jul 18, 2026
  • \(64\)
  • \(16\)
  • \(4\)
  • \(0\)
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The Correct Option is A

Solution and Explanation

For a linear transformation, \[ Y=aX+b, \] the variance is given by \[ \operatorname{Var}(Y)=a^2\operatorname{Var}(X). \] Here, \[ a=4,\qquad \operatorname{Var}(X)=4. \] Therefore, \[ \operatorname{Var}(Y) = 4^2\times4 = 16\times4 = 64. \] Hence, \[ \boxed{\operatorname{Var}(Y)=64.} \] Therefore, \[ \boxed{(A)} \] is the correct answer.
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