Since
\[
{}^nC_r={}^{\,n}C_{r-1},
\]
we have
\[
r=\frac{n+1}{2}.
\]
Now,
\[
{}^{\,n}P_{r-1}
=
\frac{n!}{(n-r+1)!}
=
9\,{}^{\,r}P_r
=
9r!.
\]
Using
\[
r=\frac{n+1}{2},
\]
and checking the given options,
\[
(n,r)=(19,10)
\]
satisfies both conditions.
Hence,
\[
\boxed{(19,10)}
\]
Therefore,
\[
\boxed{(B)}
\]