Question:

If $f(x)=3x^{2}+2xf^{\prime}(1)+f^{\prime\prime}(2)$, then $f(x)=..........$

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Constants like $f'(a)$ in an equation can be treated as unknowns and solved by differentiating the original equation.
Updated On: Jun 19, 2026
  • $3x^{2}+8x+4$
  • $3x^{2}+12x+12$
  • $3x^{2}-12x+6$
  • $3x^{2}-18x+5$
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The Correct Option is C

Solution and Explanation

Step 1: Concept
Let $f'(1) = A$ and $f''(2) = B$. Then $f(x) = 3x^2 + 2Ax + B$.

Step 2: Analysis

$f'(x) = 6x + 2A \implies f'(1) = 6 + 2A$.
So $A = 6 + 2A \implies A = -6$.
$f''(x) = 6 \implies f''(2) = 6$. So $B = 6$.

Step 3: Calculation

Substitute $A = -6$ and $B = 6$ into $f(x)$:
$f(x) = 3x^2 + 2(-6)x + 6 = 3x^2 - 12x + 6$.

Step 4: Conclusion

Hence, the function is $3x^2 - 12x + 6$. Final Answer: (C)
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