Step 1: Understand the question.
Triangle ABC has a right angle at B, so AC is the hypotenuse. We are asked whether we can pin down AC using facts about two cevians, AD and CE.
Step 2: Test Statement A alone.
Statement A only tells us D and E are midpoints of BC and AB, i.e. AD and CE are medians. It gives no lengths at all, so we cannot compute AC. Not sufficient alone.
Step 3: Test Statement B alone.
Statement B gives AD = 7 and CE = 5, but without knowing what D and E actually are (midpoints, or some other points on the sides), these two lengths cannot be tied to AC in any fixed way. Not sufficient alone.
Step 4: Combine both statements.
Let AB = c and BC = a, with the right angle at B. Since D is the midpoint of BC, \(BD = a/2\); since E is the midpoint of AB, \(BE = c/2\). Because angle B is \(90^{\circ}\), triangle ABD and triangle CBE are both right-angled at B, so:
\[ AD^2 = AB^2 + BD^2 = c^2 + \frac{a^2}{4} = 49 \]
\[ CE^2 = CB^2 + BE^2 = a^2 + \frac{c^2}{4} = 25 \]
Step 5: Solve the two equations together.
Adding the two equations:
\[ \left(c^2+a^2\right) + \frac{a^2+c^2}{4} = 74 \implies \frac{5}{4}\left(a^2+c^2\right) = 74 \implies a^2+c^2 = \frac{296}{5} \]
Since AC is the hypotenuse, \(AC^2 = a^2+c^2 = \dfrac{296}{5}\), which gives a single, definite numeric value:
\[ AC = \sqrt{\dfrac{296}{5}} = \dfrac{2\sqrt{370}}{5} \approx 7.69 \]
So once both statements are used together, AC is completely determined. Neither statement was enough by itself.
Final Answer:
\[ \boxed{\text{Statement (A) and (B) together are sufficient, neither alone is}} \]