Question:
A rice crop of 5 ha area was irrigated 10 times with 5 cm water per irrigation, find out the total quantity of water applied in cubic meter.
A rice crop of 5 ha area was irrigated 10 times with 5 cm water per irrigation, find out the total quantity of water applied in cubic meter.
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1 hectare-cm is equal to \(100 \text{ m}^3\).
Using this relationship:
\[ \text{Total quantity} = 5 \text{ ha} \times 50 \text{ cm} = 250 \text{ ha-cm} \] \[ 250 \text{ ha-cm} \times 100 \text{ m}^3\text{/ha-cm} = 25,000 \text{ m}^3 \] This dimensional analysis helps complete calculations quickly.
Using this relationship:
\[ \text{Total quantity} = 5 \text{ ha} \times 50 \text{ cm} = 250 \text{ ha-cm} \] \[ 250 \text{ ha-cm} \times 100 \text{ m}^3\text{/ha-cm} = 25,000 \text{ m}^3 \] This dimensional analysis helps complete calculations quickly.
Updated On: Jul 6, 2026
- 5000
- 10,000
- 20,000
- 25,000
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept:
The total quantity of irrigation water applied is the volume computed by multiplying the total depth of water applied by the irrigated land area.
Step 2: Key Formula or Approach:
The volume of water applied can be calculated using: \[ \text{Volume of water (m}^3\text{)} = \text{Area (m}^2\text{)} \times \text{Total depth of water (m)} \]
Step 3: Detailed Explanation:
1. Convert the area from hectares to square meters: \[ \text{Area} = 5 \text{ ha} = 5 \times 10,000 \text{ m}^2 = 50,000 \text{ m}^2 \] 2. Calculate total depth of water applied from 10 irrigations of 5 cm each: \[ \text{Total depth} = 10 \times 5 \text{ cm} = 50 \text{ cm} = 0.5 \text{ m} \] 3. Multiply the values to find total volume: \[ \text{Volume} = 50,000 \text{ m}^2 \times 0.5 \text{ m} = 25,000 \text{ m}^3 \]
Step 4: Final Answer:
The total quantity of water applied is \(25,000 \text{ m}^3\).
The total quantity of irrigation water applied is the volume computed by multiplying the total depth of water applied by the irrigated land area.
Step 2: Key Formula or Approach:
The volume of water applied can be calculated using: \[ \text{Volume of water (m}^3\text{)} = \text{Area (m}^2\text{)} \times \text{Total depth of water (m)} \]
Step 3: Detailed Explanation:
1. Convert the area from hectares to square meters: \[ \text{Area} = 5 \text{ ha} = 5 \times 10,000 \text{ m}^2 = 50,000 \text{ m}^2 \] 2. Calculate total depth of water applied from 10 irrigations of 5 cm each: \[ \text{Total depth} = 10 \times 5 \text{ cm} = 50 \text{ cm} = 0.5 \text{ m} \] 3. Multiply the values to find total volume: \[ \text{Volume} = 50,000 \text{ m}^2 \times 0.5 \text{ m} = 25,000 \text{ m}^3 \]
Step 4: Final Answer:
The total quantity of water applied is \(25,000 \text{ m}^3\).
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