Question:
A metal rod of length 0.5 m moves at $3~ms^{-1}$ perpendicular to a magnetic field of 0.2 T. The induced emf is ________.
A metal rod of length 0.5 m moves at $3~ms^{-1}$ perpendicular to a magnetic field of 0.2 T. The induced emf is ________.
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Induced EMF = (Magnetic Field) $\times$ (Velocity) $\times$ (Length).
Updated On: Jun 26, 2026
- 0.1 V
- 0.2 V
- 0.3 V
- 0.4 V
- 0.6 V
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The Correct Option is C
Solution and Explanation
Step 1: Concept
This is a case of motional electromotive force (EMF).
Step 2: Meaning
Induced EMF $e = Bvl$ for perpendicular motion.
Step 3: Analysis
$e = 0.2 \text{ T} \times 3~ms^{-1} \times 0.5 \text{ m}$.
Step 4: Conclusion
$e = 0.3 \text{ V}$. Final Answer: (C)
This is a case of motional electromotive force (EMF).
Step 2: Meaning
Induced EMF $e = Bvl$ for perpendicular motion.
Step 3: Analysis
$e = 0.2 \text{ T} \times 3~ms^{-1} \times 0.5 \text{ m}$.
Step 4: Conclusion
$e = 0.3 \text{ V}$. Final Answer: (C)
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