Concept:
This question is based on the famous
Heisenberg Uncertainty Principle, which states that it is impossible to simultaneously determine the exact position and exact momentum of a moving particle.
The mathematical expression for uncertainty principle is:
\[
\Delta x \cdot \Delta p \geq \frac{h}{4\pi}
\]
where,
\[
\Delta x = \text{uncertainty in position}
\]
\[
\Delta p = \text{uncertainty in momentum}
\]
\[
h = \text{Planck's constant}
\]
Since momentum is given by:
\[
p = mv
\]
therefore,
\[
\Delta p = m \Delta v
\]
We first calculate the uncertainty in velocity and then substitute into the uncertainty relation to determine uncertainty in position.
Step 1: Convert the given mass into SI unit.
Given:
\[
m = 50\,\text{g}
\]
Since,
\[
1000\,\text{g} = 1\,\text{kg}
\]
Thus,
\[
m = \frac{50}{1000} = 0.05\,\text{kg}
\]
Step 2: Calculate uncertainty in velocity.
Speed of the ball:
\[
v = 50\,\text{m s}^{-1}
\]
Accuracy in speed measurement:
\[
2\%
\]
Therefore,
\[
\Delta v = \frac{2}{100} \times 50
\]
\[
\Delta v = 1\,\text{m s}^{-1}
\]
Hence, uncertainty in velocity is:
\[
\Delta v = 1\,\text{m s}^{-1}
\]
Step 3: Calculate uncertainty in momentum.
Using:
\[
\Delta p = m\Delta v
\]
Substituting the values:
\[
\Delta p = 0.05 \times 1
\]
\[
\Delta p = 0.05\,\text{kg m s}^{-1}
\]
Step 4: Apply Heisenberg uncertainty principle.
We know:
\[
\Delta x \cdot \Delta p = \frac{h}{4\pi}
\]
Therefore,
\[
\Delta x = \frac{h}{4\pi \Delta p}
\]
Substituting the values:
\[
\Delta x
=
\frac{6.626 \times 10^{-34}}
{4 \times 3.14 \times 0.05}
\]
First calculate denominator:
\[
4 \times 3.14 \times 0.05
=
0.628
\]
Thus,
\[
\Delta x
=
\frac{6.626 \times 10^{-34}}{0.628}
\]
\[
\Delta x
=
1.055 \times 10^{-33}\,\text{m}
\]
Approximating:
\[
\Delta x \approx 1.06 \times 10^{-33}\,\text{m}
\]
Step 5: Write the final answer.
Hence, the uncertainty in position is:
\[
\boxed{1.06 \times 10^{-33}\,\text{m}}
\]
Therefore, the correct option is:
\[
\boxed{(B)}
\]