Step 1: Understanding the Concept:
This problem requires setting up a single-variable linear equation representing fractional parts of an unknown number.
Detailed Explanation:
Let the unknown number be $x$.
First, express the two fractional parts of $x$:
- First part:
\[ \frac{4}{15} \times \frac{5}{7} \times x = \frac{4}{21} x \]
- Second part:
\[ \frac{4}{9} \times \frac{2}{5} \times x = \frac{8}{45} x \]
According to the problem, the first part is greater than the second part by 8:
\[ \frac{4}{21} x - \frac{8}{45} x = 8 \]
To solve, find the Least Common Multiple (LCM) of 21 and 45:
- $21 = 3 \times 7$
- $45 = 3^2 \times 5$
- $\text{LCM} = 3^2 \times 5 \times 7 = 315$
Convert the fractions:
\[ \left( \frac{4 \times 15}{315} - \frac{8 \times 7}{315} \right) x = 8 \]
\[ \left( \frac{60 - 56}{315} \right) x = 8 \]
\[ \frac{4}{315} x = 8 \]
\[ x = 2 \times 315 = 630 \]
The problem asks for half of that number:
\[ \text{Half of the number} = \frac{x}{2} = \frac{630}{2} = 315 \]
Step 2: Final Answer:
Half of the number is 315, which corresponds to Option (C).